Question

5 kg object dropped from rest reaches a distance of 19.6m in how much time?



STD.10th Maharashtra State Board Syllabus

CET preparation​

Answer 1

Answer:

u=0

m=5kg

s=19.6m

g=9.8

a=g

s=ut+1/2gt^2

19.6=1/2*9.8*t^2

t^2=4

t=2

Answer 2

Explanation:

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