5 kg steam expands in a piston-cylinder device from a pressure of 5 bar and 700c (h=3925.97 kj/kg s=8.5892kj/kg-k, u=3477.52 kj/kg) to a pressure and temperature of 3 bar and 600c(h=3703.20 kj/kg s=8.5892kj/kg-k, u=3300.79 kj/kg ).If the process is reversible and adiabatic, calculate the total work(kj) for the process
nishanthsumathi99:
wt is the answer bro ????
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39990.99999 kg may be
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Answer:
Explanation:dU=d’Q-d’W
Since the process is adiabatic d’Q=0
W=dU=5(3477.52-3300.79) kj= 883.65kj
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