5 kg stone is released from rest and fall toward
earth after 4 second the magnitude of its Momentum is
Answers
Answer: 20 kg.m/s
Explanation:
momentum is mass x velocity
applying v = u + at
v = 0 + 10m/s^2(4s)
v = 40m/s
therefore, momentum = 5 kg x 40 m/s
= 20 kg.m/s
Answer:
After 4 second the magnitude of its Momentum is 98kgm/s.
Correct option is (b).
Explanation:
Initial velocity(u) = 0
Time(t) = 4seconds
Mass(m) = 2.5kg
acceleration due to gravity(g) =9.8m/s^2
Final velocity(v) = u + g x t
Final velocity(v) = 0 + 9.8 x 4
Final velocity(v) = 39.2m/s
Momentum = mass x velocity
Momentum = 2.5 x 39.2
Momentum = 98kgm/s
The given question is incomplete, the complete question is given below:-
Ques. A 2.5 kg stone is released from rest and falls toward Earth. After 4.0 s, magnitude of its momentum in kg. m/s is :
(a) 78
(b) 98
(c) 122.5
(d) 24
To know more about Momentum refer to the link below
https://brainly.in/question/54091389
To know more about Acceleration refer to the link below
https://brainly.in/question/9415862
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