Question

5 l of 0.1 M solution of sodium carbonate contains.a) 53 g b) 106g c) 10.6 g d) 1.06 g ​

Answer 1

Answer:

Answer is 53g

Explanation:

Molarity = m/M. M ×1000/volume(cm)

Molarity =0.1M

Volume =5litre=5dm^3=5000cm^3

M.M of Na2CO3=106g/mol

0.1=m/106×1000/5000

m=0.1×5000×106/1000

m=53g

Answer 2

Answer:

Above answer is correct

Explanation:

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