Math, asked by sweety6148, 3 months ago

5. Lal Singh can eat 50 laddoos in 4 hours and Pal
Singh can eat 42 laddoos in 6 hours. If both of
them start together, then what is the total time
required by them to eat 507 laddoos?
a)20 hours
b)21 hours
c)26 hours
d)25 hours

Answers

Answered by tharunraj546
2

Answer:

answer is 26 hours

Step-by-step explanation:

Lal eats 50 ladoos in 4 hour

1 hour=50/4

pal 42 in 6 hour

1 hour=7 ladoos.

both starts same time.

(50/4)+7=78/4

hours=4/78.

for 507 ladoos,

4/78X507=26

Answered by tripathiakshita48
0

Answer:

The total time required by them to eat 507 laddoos is 26 hrs

Step-by-step explanation:

From the above question,

Lal Singh can eat 50 laddoos in 4 hours and Pal Singh can eat 42 laddoos in 6 hours. If both of them start together.

Here we need to he total time required by them to eat 507 laddoos:

2n 1 hr = \frac{50}{4}

           = 12.5

Lal eats 50 ladoos in 4 hour

1 hour=50/4

Pal 42 in 6 hour

1 hour=7 ladoos.

Both starts same time:

                    = (50 / 4 ) + 7 = 78 / 4

Total hours = 4 / 78.

For 507 ladoos,

= 4 / 78 X 507 = 26

Hence, The total time required by them to eat 507 laddoos is 26 hrs

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