Chemistry, asked by vandnaindwar986, 1 month ago


5. Latent heat of vaporisation of water 10) 22•5 X10^5 J/kg (b) 22•5x10^5 j/kg (6) 22•5X 10^5 j/kg (d) 2•25 X 10^5J/kg 6. with increasing humidity the rate of evaporation (al Decreases (b) first increases and then decreases d) first decreases and then increases.​

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Answered by heroyar
1

Answer:

The latent heat of vaporisation of a water is the quantity of heat in joules required to convert 1 kilogram of the water (at its boiling point) to vapour or gas, without any change in temperature. The latent heat of vaporization of water is 22.5 × 105 joules per kilogram (or 22.5 × 105 j/kg). Hence it means that 22.5 × 10 5 J of heat is required to change 1 Kg of water (at its boiling point, 100°C) into steam at the same temperature of 100°C.

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