5. Leena has 117 rupees in the form of 5 rupee coins and 2 rupee coins. The number of
2 rupee coins is 4 times that of 5 rupee coins. Find the number of coins of each
denomination.
Answers
Given :
- Leena has 117 rupees in the form of 5 rupee coins and 2 rupee coins.
- The number of 2 rupee coins is 4 times that of 5 rupee coins.
To find :
- The number of coins of each denomination =?
Step-by-step explanation :
Let, the number of 2 rupees coins = 2x.
Then, the number of 5 rupees coins = 5x.
It is Given that :
The number of 2 rupee coins is 4 times.
•°• 2 rupees coins = 4(2x)
According to the question :
➮ 5x + 4(2x) = 117
➮ 5x + 8x = 117
➮ 13x = 117
➮ x = 117/13
➮ x = 9.
Therefore, We got the value of, x = 9.
Hence,
The number of 2 rupees coins, 4(2x) = 8 × 9 = 72 coins
The number of 5 rupees coins, 5x = 5 × 9 = 45 coins
Leena has 117 rupees in the form of 5 rupee coins
and 2 rupee coins . The number of 2 rupee coins
is 4 times that of 5 rupee coins . Find the number of coins of each denomination.
The number of 2 rupees coins :
The number of 5 rupees coins :
►Leena has 117 rupees in the form of 5 rupee coins and 2 rupee coins.
►The number of 2 rupee coins is 4 times that of 5 rupee coins.
The number of coins of each denomination
We are given,
Leena has 117 rupees in the form of 2 rupee coins and 5 rupee coins.
➪Let, the number of 2 rupees coins = 2m.
➪the number of 5 rupees coins = 5m.
By given condition,
We get ,
➪The number of 2 rupee coins is 4 times.
⛬ 2 rupees coins = 4(2m)
⛬ 5m + 4(2m) = 117
⛬ 5m + 8m = 117
⛬ 13m = 117
⛬ m = 117/13
⛬ m = 9.
Hence,
The number of 2 rupees coins, 4(2) = 8 × 9 = 72 coins
The number of 5 rupees coins, 5×m = 5 × 9 = 45 coins