5, Let ARC be a triangle such that AB = 6 V3 cm, AC = 12 cm
and BC = 6 cm. Angle B is
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Step-by-step explanation:
hii ....
here your answer...........
use this formula.
b^2=c^2+a^2-2cacos(B).
let here b=12 cm.
c=6root(3)cm
a=6cm.
so...
12^2=[6root (3)]^2+6^2-2*6root(3)*6*cos(B).
144=144-36root(3)cos(B).
So ...cos(B)=0.
B=cos^-1(0).
B=90°.
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