5. Let U = {4,8,12,16,20,24,28} A = {8,16,24} and B = {4,16,20,28} .
Find (A U B) and (A u B)l.
Answers
Answered by
14
Hi ,
It is given that ,
U = { 4,8,12,16,20,24,28 }
A = { 8, 16 ,24 }
B = { 4 , 16 , 20 , 28 }
Now ,
i ) A U B = { 8 , 16 ,24 } U { 4,16,20,28}
= { 4 ,8 ,16 ,20 , 24 , 28 }
ii ) ( A U B )' = U - ( A U B )
= { 4,8,12,16,20,24,28 } -
{4,8,16,20,24,28 }
= { 12 }
I hope this helps you.
: )
It is given that ,
U = { 4,8,12,16,20,24,28 }
A = { 8, 16 ,24 }
B = { 4 , 16 , 20 , 28 }
Now ,
i ) A U B = { 8 , 16 ,24 } U { 4,16,20,28}
= { 4 ,8 ,16 ,20 , 24 , 28 }
ii ) ( A U B )' = U - ( A U B )
= { 4,8,12,16,20,24,28 } -
{4,8,16,20,24,28 }
= { 12 }
I hope this helps you.
: )
Answered by
5
Question :
Let U = {4,8,12,16,20,24,28} A = {8,16,24} and B = {4,16,20,28} .
Find (A U B)’ and (A ∩ B)’
Union of two sets :
The union of the sets A and B is the set of all the element that belongs to either A or B or both. It is denoted by A U B(“A union B”).
Intersection of two sets :
The intersection of the sets a and b is the set of all the elements which belong to both A and B. It is denoted by A ∩ B (“ A intersection B”).
•If A and B do not have any element in common then A ∩ B= a null set = Ø
•A’ == The complementary set of A
• To find A’ , list all the members of the universal set U which are not members of A.
(A U B )’ = A’ ∩ B’
(A ∩ B )’ = A’ U B’
SOLUTION :
GIVEN :
U = {4,8,12,16,20,24,28} A = {8,16,24} and B = {4,16,20,28}
A U B = {4,8,16,20,24,28}
Hence, (A U B )’ = U - A U B
(A U B )’ = {12}
A ∩ B = {16}
Hence,(A ∩ B )’ = U - (A ∩ B )
(A ∩ B )’ = {4.8,12,20,24,28}
HOPE THIS WILL HELP YOU….
Let U = {4,8,12,16,20,24,28} A = {8,16,24} and B = {4,16,20,28} .
Find (A U B)’ and (A ∩ B)’
Union of two sets :
The union of the sets A and B is the set of all the element that belongs to either A or B or both. It is denoted by A U B(“A union B”).
Intersection of two sets :
The intersection of the sets a and b is the set of all the elements which belong to both A and B. It is denoted by A ∩ B (“ A intersection B”).
•If A and B do not have any element in common then A ∩ B= a null set = Ø
•A’ == The complementary set of A
• To find A’ , list all the members of the universal set U which are not members of A.
(A U B )’ = A’ ∩ B’
(A ∩ B )’ = A’ U B’
SOLUTION :
GIVEN :
U = {4,8,12,16,20,24,28} A = {8,16,24} and B = {4,16,20,28}
A U B = {4,8,16,20,24,28}
Hence, (A U B )’ = U - A U B
(A U B )’ = {12}
A ∩ B = {16}
Hence,(A ∩ B )’ = U - (A ∩ B )
(A ∩ B )’ = {4.8,12,20,24,28}
HOPE THIS WILL HELP YOU….
Similar questions