Question

5.
Light travel with velocities 2 * 108 m/s and
2.25 x 108 m/s through two different media. The
critical angle between the two media is
(1) sin"61) (2) sin 1 (2)
(3) sin")
(4) sin​

Answer 1

Critical angle = Sin⁻¹(4/5)

Explanation:

Given: Light travels with velocities 2.5 * 10^8 m/s and 2 * 10^8 m/s through two different media.

Find: The critical angle of the interface.

Solution:

Sin C = M2 / M1

We know that M is inversely proportional to V

So M = C/V

Sin C = V1/ V2

   = 2 * 10^8 / 2.5 * 10^8

   = 2/2.5

Sin C = 4/5

Therefore, C = Sine inverse of 4/5

Critical Angle of interface = 53.13°