Question

5. Line / is the bisector of an angle 2 A and B is any
point on I. BP and BQ are perpendiculars from B
to the arms of Z A (see Fig. 7.20). Show that:
(i) A APB = AAQB
(ü) BP = BQ or B is equidistant from the arms
of angle A​

Answer 1

Step-by-step explanation:

in triangle APB= triangle AQB

angle APB = angle ADB ( from 2)

angle PAB=angle QAB (from 1)

AB = AB ( common )

triangle APB = triangle AQB ( AAS )

therefore BP= BQ ( cpct)