5 lit of nitrogen on combining with 15 lit of hydrogen will produce lit of ammonia
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Answer:
Balanced equation:
N2 + 3H2 → 2NH3
3 L H2 produce 2 L NH3
multiply by 5
15 L H3 produce 10 L NH3
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☀️Hydrogen and nitrogen reacting to form ammonia is a reversible reaction, so it depends on the reaction conditions.
☀️If you look at the stoichiometry of the reaction, you can see that 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to form 2 moles of ammonia gas.
☀️N2 + 3H2 → 2NH3
☀️Using Le Chatelier's principle, increasing the pressure of the system would increase yield of ammonia as there are fewer moles of gas on the right side.
☀️Also if you increase the temperature (as the enthalpy change in the forward direction is negative, so it is exothermic) you decrease the yield.
☀️This is typically balanced against the rate of reaction - which increases with temperature - in industry.
☀️If theoretically you managed to get 100% yield and 15 litres of hydrogen, you'd need 5 litres of nitrogen to obtain 10 litres of ammonia.
☀️This is because a litre of gas has roughly the same amount of molecules regardless of the type of molecule when you keep the pressure and temperature the same (pV = nRT, ideal gas equation if you want to look into it).
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