Question

5 Litre of a gas weights 14.4 g At NTP. calculate the weight​

Answer 1

$no. \: of \: moles \: of \: gas \: at \: ntp \\ n= \frac{v}{vm}$

where,

n=no. of moles of gas

v=volume of gas in L

vm= molar volume in L which is at STP=22.7 L,and at NTP=22.7 L

Given,

v=5 L

vm= 22.7 L (as gas is at NTP)

putting values in above formula,

$n = \frac{5l}{22.7l}$

$n = 0.220 \: moles$

also ,

$n = \frac{given \: mass}{molar \: mass}$

n=no. of moles

given mass= 14.4 g

putting values ,we get

$0.220= \frac{14.4}{mm}$

upon solving,

$m = 3.168 \: grams$