Question

5 litres of kerosene oil is found to weigh 4.40 kg.
Find the density of kerosene oil in
(a) CGS system,
(b) SI system.​

Answer 1

Answer:

density=mass/volume

=4.4/1

=4.4 kg/l

Answer 2

Given :

• Number of litres of kerosene oil =5litres

• Weigh=4.40kg

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To Find :

• The density of kerosene oil in

(a) CGS system

(b) SI system

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Formula :

As we know that,

$\red \bigstar \sf \: 1 \: litres = 1 \times 1000 {cm}^{3}$

$\\ \red \bigstar \sf \: 1kg = 1000g$

$\\ \red \bigstar \sf \: density = \frac{mass}{volume}$

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Solution :

Given volume of kerosene oil =$\sf{5litres \: \: }$

Volume of kerosene oil =$\sf{5 \times 1000cm^{3}}$

•Mass=4.40kg=$\sf{4.40 \times 1000g}$

Mass=$\sf{4.40 \times 1000g}$

$\\ \bf \mapsto density = \frac{mass}{volume}$

(a) In CGS system,

$\\ \implies \sf \: density = \frac{mass}{volume} \\ \\ \implies \sf \: density = \frac{4.40 \times 1000 \: g}{5 \times 1000 {cm}^{3} } \\ \\ \implies \sf \: density = \frac{4.40}{5} \frac{g}{ {cm}^{3} } \\ \\ \implies \sf \: density = 0.88g {cm}^{ - 3} \\ \\ \implies \boxed{ \sf{density = 0.88g {cm}^{ - 3} }}$

(b) In SI system,

$\\ \implies \sf \: density = \frac{mass}{volume} \\ \\ \implies \sf \: density = \frac{0.88}{1000} \times 100 \times 100 \times 100 \\ \\ \\ \implies \sf \: density = 880kg {m}^{ - 3} \\ \\ \implies \boxed{ \sf{density = 880kg {m}^{ - 3} }}$

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More formulas :

➡ For Finding pressure of an object we use ,

$\red \bigstar \boxed{ \sf{pressure = \frac{normal \: force}{area} }}$

➡ For Finding force of an object or a body we use,

$\\ \red \bigstar \boxed{ \sf{force = mass \times acceleration}}$

➡ For Finding power of an object we use,

$\red \bigstar \boxed{ \sf{power = \frac{energy}{time} }}$

➡ For Finding Intensity of an body or a object we use,

$\red \bigstar \boxed{ \sf{intensity = \frac{energy}{area \times time} }}$

➡ For finding the value of $\sf{\omega}$ , we use

$\\ \red\bigstar\boxed{\sf{\omega=\dfrac{2 \pi}{t}}}$