5 loaf of bread and 3 tins of sadin cost 35 cedis and 2 loaf of bread 2 tins of sadin cost 18 cedis .What is the cost of 3 loafs of bread and 2 tins of sadin?
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Answer:22 cedis
Step-by-step explanation:Let the loaf of bred be 'b' and tins of saldin be 's'
5b+3s=35
2b+2s=18
(5b+3s=35)2=10b=6s=70------>Equ-1
(2b+2s=18)2=10b+10s=90------>Equ-2
Equ-2 minus Equ-1 = 4s=20
s=20/4
s=5
Substituting s=5 in Equ-1
10b+30=70
10b=70-30=40
b=40/10
b=4
Total cost=3*4+2*5
=12+10
=22
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