Question

5√log5^7 - 7√log7^5​

Answer 1

Step-by-step explanation:

There's nothing here to "solve".....just to evaluate..

√7^(log 5) - √5^(log 7) =

[7^(1/2)]^(log 5) - [ 5^(1/2)]^(log 7)=

[ 7] ^[ (1/2)log(5) ] - [5]^[ (1/2)log(7)]

[7] ^ [log √5] - [5]^[log √7 ] note that we can write

[10^(log7)]^[log5] - [10^(log 5)]^[log 7]

10 ^(log7 * log 5) - 10^(log 5 * log 7) =

10^(log5 * log 7) - 10^(log 5 * log7) =

0

Then.....it appears that we have the property that

a^(log b) - b^(log a) = 0

Answer 2

Answer:

finally done with answer, answer in attachment..

please mark it as brainlist