Question

5 m long wire carrying a current of 5a. It experience a force of 7.5 n when placed in uniform magnetic field of intensity 2t.The angle between magnetic fields and direction of current is

Answer 1

Explanation:

5 m long wire carrying a current of 5a. It experience a force of 7.5 n when placed in uniform magnetic field of intensity 2t.The angle between magnetic fields and direction of current is Heating Effect of Current.

Answer 2

☆$\red {HELLO\:DEAR}$☆

It is given that,

Current, I = 5 A

Length of wire, L = 1.5 m

force, F = 7.5 N

Magnetic field, B = 2 T

Force acting on a conductor of length 1.5 m is given by :

F=ILB SIN0

SIN0=F/ILB

SIN0=7.5N/5A×1.5M×2T

SIN0=0.5

0=30°

Hence, the angle between the magnetic field and the direction of the current is 30°

☆$\green {VISHU\:PANDAT}$☆

☆$\blue {FOLLOW\:ME}$☆