5. M (m, 2m+1) is a solution of the equation.
3x+4y=26. Find the value of m.
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Since M(m,2m+1) is a solution of the equation,
The value of abscissa and ordinate of M satisfy the equation 3x+4y=26.
Substituting x by m and y by 2m+1 in the equation, we have:-
3(m)+4(2m+1)=26
=>3m+8m+4=26
=>11m=26-4
=>11m=222
=>m=22/11=2
Thus, value of m=2
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