5. M. Trevor needs to drive for 565 miles, if he
dove 245 miles in the morning and 112 mies in
the afternoon how many more mies does M.
Trevor have left to rive?
Answers
First we have to find how much he has travelled :
245 + 112 = 357
So the distance left to travel is :
565 - 357 = 208 miles
Therefore he needs to cover another 208 Miles
Hope it helps and pls mark Brainliest
Answer:
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pjagadish27
Aug 28, 2013
I just went through this thread and I have a doubt. Applying Karishma's method of using units, in this case, we get
(25*10+40*50)/(10+ 50) . The units are (miles/g * miles)/ miles = miles/gallon. Please point out the mistake in my logic.
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VeritasKarishma
EXPERT'S
POST
Aug 28, 2013
pjagadish27 wrote:
I just went through this thread and I have a doubt. Applying Karishma's method of using units, in this case, we get
(25*10+40*50)/(10+ 50) . The units are (miles/g * miles)/ miles = miles/gallon. Please point out the mistake in my logic.
We need total miles in the numerator and gallons in the denominator.
(C1*W1 + C2*W2) should make "miles".
(W1 + W2) should make "gallons".
_________________
Karishma
Veritas Prep GMAT Instructor
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VeritasKarishma
EXPERT'S
POST
Feb 5, 2015
A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
A. 28
B. 30
C. 33
D. 36
E. 38
I do not understand why weighted average method fails here.
Methods don't fail. You might need to manipulate them in particular circumstances.
You need to understand that whatever is given cannot be the weight. For example, when trying to find the average profit, the weight must be cost price, not number of items or selling price. Similarly, when calculating average speed, weight must be time, not distance. In the same way, here the weight must be amount of fuel used, not distance traveled.
How do you figure out what the weight will be in each case? The units help you in figuring that out.
Check: http://www.veritasprep.com/blog/2014/12 ... -averages/
_________________
Karishma
Veritas Prep GMAT Instructor
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SravnaTestPrep
EXPERT'S
POST
May 29, 2017
leafsrule99 wrote:
A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
A. 28
B. 30
C. 33
D. 36
E. 38
1. Since mileage is varying according to city or highway, average is calculated by total miles traveled / total gallons used
2. Total miles traveled=60
3. total gallons used = gallons used in city + gallons used in highway= 10/25 + 50/40= 33/20
4. So average is 60/(33/20)=36(approx)
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ScottTargetTestPrep
EXPERT'S
POST
Apr 23, 2019
enigma123 wrote:
A certain car averages 25 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
A) 28
B) 30
C) 33
D) 36
E) 38
We can use the formula:
average = total distance/total gallons
average = 60/(10/25 + 50/40)
average = 60/(2/5 + 5/4)
average = 60/(8/20 + 25/20)
average = 60/(33/20)
average = 1200/33 ≈ 36