Question

5. M2CO3 + 2HCl→ 2MCl + H2O + P↑

MHCO3 + HCl → MCl + H2O + Q↑

2MHCO3 ∆→ M2CO3 + H2O + S↑

The correct one with respect to P, Q, S is/are [ ]

a) Ca(OH)2 + excess

P → CaCO3 + H2O

b) Ca(HCO3

)2 + Ca(OH)2 → 2CaCO3 + S↑

c) Ca(OH)2 + Q → Ca(HCO3)2 + H2O

d) 2NaHCO3 + H2SO4 → Na2SO4 + 2H2O + P↑​

Answer 1

Answer:

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Answer 2

Answer:

The correct option is the option d 2NaHCO3 + H2SO4 → Na2SO4 + 2H2O + P↑​

Explanation:

The given reaction in the question is a reaction of the carbonates and the hydrogen carbonates of any metal with acid, and decomposition of the latter respectively. As we know that whenever any type of strong acid reacts with the metal carbonates or its hydrogen carbonates it completes with the formation of corresponding metallic salt water and carbon dioxide evolution.

In the following given options, the last one also completes with the formation of carbon dioxide indicated as P. Therefore is the correct option as in the P, Q, S is also the same gas.

$2NaHCO_{3} + H_{2} SO_{4}$ → $Na_{2}SO_{4} + 2H_{2} O + CO_{2}$↑