5 marks Question
(From Vikas pre university college)
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here's your expected answer in the given attachment
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Let a triangle ABC whose base = 3 cm and leg = 4cm
According to Pythagoras theorem
(AB)^2 + (BC)^2 = (AC)^2
(4)^2 + (3)^2 = (AC )^2
16 + 9 =(AC)^2
5 = AC
Given r = 3 , l = 5
So, SA of cone is 22/7 × 3 ×5 + 22/7 × 9
= 330/7 + 198/7 = 528/7 = 75.428
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