Question

5 marks question long answer type

dont spam​

Answer 1

Answer:

500 Bananas

Step-by-step explanation:

Let Say node A  has  A bananas

& Node B  has  B bananas

Amount received = 2A/3   + B = 400

=> 2A + 3B = 1200  - eq 1

A + 4B/5  = 460

=> 5A + 4B = 2300   - eq 2

3* eq2 - 4 * eq 1

=>  15A - 8A = 6900 - 4800

=> 7A = 2100

=> A = 300

2* 300 + 3B = 1200

=> B = 200

Total Bananas = 300 + 200 = 500

Answer 2

⚡⚡Here is the answer⚡⚡

Let the number of bananas in lots A and B be x and y, respectively

CASE. 1. Cost of the first lot at the rate of Rs.2 for 3 bananas + Cost of the second lot at the rate of Rs. 1 per bananas = Amount received

=> 2/3 x + y = 400

=> 2x + 3y = 1200

CASE. 2. Cost of the first lot at the rate of Rs. 1 per banana + Cost of the second lot at the rate of Rs. 4 for 5 bananas =Amount received

x+4/5y=460

=> 5x+4y=2300

On multiplying, we get,

x=300

Now putting the value of Eq(i) we get

y=200

:-Total no. of bananas=Number of bananas in lot A + Number of bananas in lot B =x+y

=300+200=500

Hence, he had 500 bananas.