Question

5 marks question long answer type

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Answer 1

here is your answer in the attachment given above

Answer 2

Answer:

Given : ∆ABC in which DE||BC and AD=DB

To Prove : AE = AC

Proof :

Since , DE||BC

$\frac{AD}{DB} = \frac{AE}{EC}$

----- by BPT

$1 = \frac{AE}{EC}$

----- as AD = DB

So , AE = EC