Question

5 marks question long type

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Answer 1

⚡⚡Here is your answer ⚡⚡

Let the cost of a pen be Rs. X and the cost of a pencil box be Rs. Y .

Then, by given condition,

4x+4y=100=>x+y=25..........(i)

and. 3x=y+15

=> 3x-y=15............(ii)

On adding Eqs.(i)and (ii), we get

4x=40

=> x=10

By substituting x=10, in Eq (i) we get

y=25-10=15

Hence, the cost of a pen and a pencil box are Rs.10 and Rs.15, respectively.

⭐Mahir⭐

Answer 2

Solution :-

Let the cost of a pen be Rs 'x' and the cost of a pencil box be Rs. 'y'

As, the cost of 4 pens and 4 pencil boxes is Rs. 100

So, 4x + 4y = 100 .................(1)

And, three times the cost of a pen is Rs. 15 more than the cost of a pencil box.

So, 3x = y + 15

⇒ 3x - y = 15 ......................(2)

Now multiplying the equation (1) by 3 and equation (2) by 4, we get

⇒ (4x + 4y = 100)*(3) = 12x + 12y = 300 ................(3)

⇒ (3x - y = 15)*(4) = 12x - 4y = 60 ..........................(4)

Now, subtracting (4) from (3)

  12x + 12y = 300

  12x -  4y   = 60 

 -      +         -

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         16y = 240

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⇒ 16y = 240

⇒ y = 240/16

⇒ y = 15

Now, substituting the value of y = 15 in (2)

⇒ 3x - y = 15

⇒ 3x - 15 = 15

⇒ 3x = 15 + 15

⇒ 3x = 30

⇒ x = 30/3

⇒ x = 10

So, the cost of a pen is Rs. 10 and the cost of a pencil box is Rs. 15.

HOPE IT HELPS YOU....