Math, asked by riyayagyik, 1 year ago

5 men , 6 women and 7 boys finished a work in 3 days and get the remuneration of 2137.50 . if 1 men , 1 women and 1 boy in one day be in the proportion of 1/2:1/3:1/4, what sum did each man get on a day

Answers

Answered by danielochich
13
The proportion; men: women: boys = 5x1/2 : 6x1/3 : 7x1/4
                                                         = 5/2 : 2 : 7/4
                                                         = 2.5 : 2 : 1.75

Total = 2.5 + 2 + 1.75 = 6.25

Men's share = 2.5/6.25 x 2137.50 = 855 in 3 days

Share per day = 855/3 = 285

Share per man = 285/5 = 57

So, each man gets 57 per day
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