Question

5 men or 8 women do equal amount of work in a day. a job requires 3 men and 5 women to finish the job in 10 days. how many woman are required to finish the job in 14 days?

Answer 1

Lets assume total LCM(5,8) = 40units.
As, 5 men or 8 women do equal amount of work in a day,
1 Man does 8units/day and 1 Woman does 5units/day.
3M and 5W in 10 days do (3*8 + 5*5)*10 = 490units
To do 490 units in 14 days, number of Women required = 490/(14*5) = 7

Answer 2

Answer:

Number of Women required = 7

Step-by-step explanation:

• consider, LCM of $5$,$8$= $40$units.

• $5$ men and $8$ women can do the same work in a day.
• $1$ man → $8$ units per day

• $1$ woman→$5$ units per day

• 3M and 5W in 10 days

                $=(3*8+5*5)*10=490$ units

$490$ units in 14 days, number of Women required = $\frac{490}{(14*5)} =7$

work from days:

• The questions in the work from days section will require you to determine how much work you and I can do in a certain length of time.
• The work-from-days segment can be simply handled by applying some fundamental ideas and the formulae that we will build, much like the concept of days from work.

• We start with the work's formula. where work is the task's monetary worth.$Work = Number of days (Time) (T or D) * Number of men (M).$

                                (or)

                      $W = D *M.$

• Assume that in the first example, w1 represents the work completed, and in the second, w2.
• Let's also assume that T1 represents the first person's duration and T2 represents the second term's duration.
• Additionally, let N1 and N2 stand for the respective numbers of workers for each task.
• Consequently, the ratio of the first task's work to the second task's work is equal to$w1/w2 = (T1 *N1)/(T2 * N2).$

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