5 metre 60 cm high vertical pole easts a Shadow 20 cm long. find at the same time.
i) the length of the shadow cast by another pole 10m 50cm high.
ii) the height of a pole which casts a shadow 5metre long.
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Answer:
Let x m be the length of the pole whose shadow is of length 10m50cm.
Let y m be the length of the pole whose shadow is 5m long.
Clearly, it is a case of direct variation.
i)
3.20
5.60
=
x
10.50
x=
5.60
10.50×3.20
=6
Hence, the length of the shadow is 6m.
ii)
3.20
5.60
=
5
y
x=
3.20
5.60×5
=8.75
Hence, the length of the pole is 8.75 meters.
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