Question

5 mg radioactive sample 90% disintegrate in 3 years
then 99% disintegration will be in​

Answer 1

Explanation:

k= 2.303/t log a/a - x

k= 2.303/3 log 100/100-90

so k= 2.303/3 log 100/10

k= 2.303/3 ( bcz log 10=1)

now, k= 2.303/t log 100/100-99

k=2.303/t log 100/1

so now t= 2.303×3/2.303 2 log 10

=3×2log10

=6