5 ml of gaseous hydrocarbon is exposed to 30ml of O2 the resultant gas on cooling is on to measure 25 ml of which 10 ml absorbed by NIOS and the remaining by determine the molecular formula of hydrocarbon
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Answer:
Hey there here is your answer
Explanation:
Let the formula of hydrocarbon =CxHy
∴CxHy+(x+y4)O2→xCO2+y2H2O
Initial1mL(x+y4)mL00 ltbgt Final5mL5(x+y4)mL5xmLm−
CO2=10mL
∴5x=10⇒x=2mL
Volume of O2 left =15mL
Volume of O2 used =30−15=15mL.
∴5(x+y4)=15⇒y=4
Formula of hydrocarbon =C2H4
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