Question

5 ml of N HCl, 20 ml of N/2 H2SO4 and 30 ml of N/3 HNO3 are mixed together and

volume made to one litre. The normality of the resulting solution is​

Answer 1

Answer:

We know

Meq= N × V

where Meq is the equivalent molarity

N is normality of the solution

V is volume of solution

Applying the formula to each of the solution separately

1) HCl

Meq= 1× 5 = 5M

2) H2SO4

Meq=

2

1

×20=10 M

3) HNO3

Meq=

3

1

×30=10 M

For total solution

Meq = M1 + M2 + M3

Meq = 5+10+10 = 25 M

and volume = 1000 mL

Thus applying the same formula

Meq= N × V

25 = N× 1000

N= $$\dfrac{25}{1000} N

=

40

N

Thus normality of the solution would be

40

N

.