Question

5 ml of n hcl, 20 ml of n/2 h2so4 and 30 ml of n/3 hno3 are mixed together and volume made to 1 l. the normality of resulting solution is

Answer 1

As we know M(eq) = N x V

where
M(eq) = equivalent molarity
N = normality of solution
V = volume of solution

Applying this formula for each we get

For HCl----------M(eq) = 1 x 5 = 5M

For H₂SO₄---------M(eq) =  1/2 x 20 = 10M

For HNO₃----------M(eq) = 1/3 x 30 = 10M

For total soluion, M(eq) = M₁ + M₂ + M₃

M(eq) = 5 + 10 + 10 = 25M

and volume = 1000 mL

Applying same formula M(eq) = N x V

25 = N x 1000

N = 25 / 1000

Normality = 0.04 N

Answer 2

Answer:

N/40

Explanation:

Eq= N x V

For HCl

Eq= 1 x 5 = 5 Eq

For H2SO4

Eq = 1/2 x 20 = 10 Eq

For HNO3

Eq= 1/3 x 30 = 10 Eq

Total Eq = 5+10+10 = 25 Eq

Again,

Eq= N x V

25 = N x 1000

N/40 Ans