Science, asked by psilvei18, 10 months ago

5 ml of water and 10ml of concentrated sulphuric acid are to be mixed in a
beaker.
i) Describe the procedure to be followed.
ii) What is the process called?
iii) What happens to the hydronium ion concentration when the process is
carried out.

Answers

Answered by SwaggerGabru
1

Answer:

I) Process: 1. Take 10 mL water in a beaker. 2. Take 15 mL of sulphuric acid. 3. Pour the acid in beaker contains water. 4. Touch the beaker. 5. We feel the beaker is to hot means this is an exothermic reaction. ii)This process is called dillution of concentrated acids.

Read more on Brainly.in - https://brainly.in/question/3994823#readmore

Answered by tusharraj77123
1

Answer:

1 . IT WILL MIX

2. 15 ML OF CONCERTRATED SULPHURIC

3. IT WILL BECOME CONCERTED SULPHURIC

MARK IT AS BRAINLEST ANSWER PLEASE

Similar questions