5 molal aqueous solution of a weak acid (hx) is 20% ionized. if kf for water is 1.86 k kg mol-1, the lowering in freezing point of the solution is
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HX →H
+
+X
−
weak acid 0 0
1-a a a
a = 20% dissociation
i=(1−a)+a+a=1+a=1+0.2=1.2
ΔT
f
=i×K
f
×m
=1.2×1.86×0.5
=1.12K
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