5 mole each of two ideal gases a and b are taken in a container and expanded reversibly and adiabatically, during this process temperature of gaseous mixture decrease from 350k to 250 k find
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Hey dear,
I think you want to find work done in expansion here.
● Answer -
W = 8.314 kJ
● Explaination -
# Given -
n = 5 + 5 = 10 mol
T1 = 350 K
T2 = 250 K
# Solution -
Work done in expansion is calculated by formula -
W = -nR∆T
W = -10 × 8.314 × (250-350)
W = 8.314×10^3 J
W = 8.314 kJ
Hence, work done during process of expansion is 8.314 kJ.
Hope this helped...
I think you want to find work done in expansion here.
● Answer -
W = 8.314 kJ
● Explaination -
# Given -
n = 5 + 5 = 10 mol
T1 = 350 K
T2 = 250 K
# Solution -
Work done in expansion is calculated by formula -
W = -nR∆T
W = -10 × 8.314 × (250-350)
W = 8.314×10^3 J
W = 8.314 kJ
Hence, work done during process of expansion is 8.314 kJ.
Hope this helped...
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