5 mole of dihydrogen react with 5 moles of dinitrogen calculate mole of ammonia
Answers
Explanation:
N2(g) + 3H2(g) →2NH3(g)
28g 6g 34g
28 g of N2 reacts with 6g of H2.
1g of N2 reacts with 6/28 g of H2
2000g of N2 will react with 2000 × 6/28
= 428.57 of H2
but H2 is given 1 × 10³g is greater than 428.57 g
N2 is a limiting reagent and limits the production of ammonia
28g of N2 produces 34 g of NH3
1g of N2 produces 34/28 g of NH3
2000g of N2 will produce 34/28 × 2000
= 2428.57 g of NH3.
(ii) H2 is excess, so it remains unreacted
(iii) Mass of unreacted dihydrogen = 1000-428.57
=571.43g
Check out the video for more details on chemical reactions
3,525
Refer more
What happens in a combination reaction? Explain.
Balance the equation N2 + H2 → NH3
Give an example of a combination reaction between two elements.
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Explanation:
5 moles of dihydrogen react with 5 moles of dinitrogen calculate the moles of Ammonia product.
