Question

5 moles of ba(oh)2 are treated with excess of co2 .How muchbaco3 will be formed

Answer 1

Answer:

Explanation:

The reaction will be :

Ba(OH)2 + CO2 →BaCO3 + H2O

It can be calculated by using POAC (Principle of atomic conservation) :

Barium atoms in Ba(OH)2 in reactant = Barium atoms in BaCO3 in product

Number of moles of BaCO3 = 0.205 mol

​Molar mass of BaCO3 :

137.4 + 12 + 3×16 = 197.4 g

Hence , mass of BaCO3 = Number of moles ×Molar massMass = 0.205 ×197.4 = 40.467 g