5 moles of CH4
is burned with 8 moles of O2
than calculate mole of CO2
formed and remaining
moles of excess reagent
(A) 4,1 (B) 1,4 (C) 0,5 (D) 5,0
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CH⁴+2O²------>CO²+2H²O
if we multiply by 4 we get
4CH⁴+8O²--------->4CO²+8 H²O
4 MOLES OF CO²IS PRODUCED
A)4,1
here is your answer
Answered by
0
Answer:
option A
Explanation:
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