Question

5 moles of nitrogen gas is in a 100 litre fixed cylinder at 300 k what is the pressure of the gas​

Answer 1

Answer:

The reaction involved, dissociation of nitrogen gas

N

2

⇌2N

mass of nitrogen =1.4g

⇒moles=1.4/28=0.05

moles after dissociation of N

2

=0.05×70/100

and after dissociation of 2N=0.05×2×30/100

total moles involved =0.065

applying ideal gas equation (PV=nRT)

P=(nRT)/V

=1.92atm