Question

'5' moles of oxygen is heated at constant
volume from 10°C to 20°C. What will be
the change in the internal energy of the
gas in calories?
For the gas Cp = 7 cal/gm mole/°C and
R = 2 cal/moPC - Cal
(A) 50
(B) 100
(C) 150
(D) 250​

Answer 1

Explanation:

R=8.31Jmol−1deg−1=4.188.31cal mol−1deg−1

=1.99cal mol−1deg−1

We know that CP−CV=R

or CV=CP−R=7.03−1.99=5.04cal mol−1deg−1

Heat absorbed by 5 mole of oxygen in heating from 10oC to 20oC

=5×CV×ΔT=5×5.04×10=252cal

Since, the gas is heated at constant volume, no external work is done,

i.e., w=0

So, change in internal energy will be equal to heat absorbed,

ΔU=q+w=252+0=252cal

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