Question

5 moles of SO and 5 moles of O   are allowed to react. At equilibrium, it was found that 60% of SO is used up. lf the partial pressure of the equilibrium mixture is one atmosphere. the partial pressure of O   is

Answer 1

The reaction is SO + 1/2 O2 →→→ SO2

Thus if 60% of SO is used up, by stoichiometry , the number of moles of O2 used = 1/2 of 60% of 5 moles = 1.5 moles

and number of moles of SO2 formed
= 60% of 5 moles = 3 moles
Thus total number of moles = (2+3.5+3) = 8.5

Thus partial pressure if O2 = (3.5/8.5)*1 atm = 0.412 atm