Question

5 moles of SO, and 5 moles of O, are allowed to react to
form sulphur trioxide, in a closed vessel. At the equilibrium stage
60% of sulphur dioxide is used up. The total number of moles of
sulphur dioxide, 0, and sulphur trioxide, in the vessel now is
(1) 10.0 (2) 8.5 (3) 10.5 (4)3.9​

Answer 1

Answer:

8.5

Explanation:

SO2+1/2O2---------->SO3

5mole + 5mole --------> 0 mole

5-5(0.6) + 5-5(0.3)---------> 5(0.6)

2. + 3.5 3

8.5