Question

5 moles of SO2 and 5 moles of O2 reacting with each other to form SO3. determine limiting reagent, weight of excess reagent left and amount of SO3 formed .
Give stepwise answer please

Answer 1

2so2+O2 gives rise to 2so3
so2 is limiting reagent
O2 is excess reagent
2moles of so2 requires 1 mole of 02
5mole of so2 -2.5 moles of o2
5so2+5o2gives rise to 5so3+2.5o2
so3 formed is 400g
O2 left is 80 g