5^n×25^n-1÷(5^n-1×25^n-1)
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{5^n * 5^(2n-2)} / {5^(n-1) * 5^(2n-1)}
as 5^(2n-1) is same in both, it will divide.
(5^n)/(5^(n-1)
as both denominator and numerator has same base(5), 5^(n-1) then after going on numerator this will be minus
then
5^{n-(n-1)}
5^(n-n+1)
5^1
=5
i hope this will help you
as 5^(2n-1) is same in both, it will divide.
(5^n)/(5^(n-1)
as both denominator and numerator has same base(5), 5^(n-1) then after going on numerator this will be minus
then
5^{n-(n-1)}
5^(n-n+1)
5^1
=5
i hope this will help you
Stutigupya11:
thanks
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