Question

5. O.N. of Ni in Ni(CO)4 is: (a) o (b) 2 (c) 4 (d) 6​

Answer 1

The oxidation state of Ni in Ni(CO)4 is 0(zero).

Let the oxidation number of Ni be x.

We can see that the overall charge on the complex is 0.

Thus, the sum of charge of all the individual elements in the complex should be equal to 0.

Therefore, x + 4(0) = 0

                  x = 0

Hence, the oxidation number of Ni in Ni(CO)4 is 0.