5 % of sulphur is present in insulin . the minimum molecular weight of insulin is
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mass by mass % of a solution=(mass of solute /mass of solution)×100
% of sulphur=5
5=32/x×100
x=3200/5
x=840
min. molecular mass of insulin is 870g
% of sulphur=5
5=32/x×100
x=3200/5
x=840
min. molecular mass of insulin is 870g
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