Math, asked by kanchansuyal82, 2 months ago

5% of the population of a town were killed in an earthquake and 8% of the remainder left if in the population of the town now is 43700 what was its population at the beginning

plz explain it step by step verrrryyyy clearly​

Answers

Answered by sarasijagonapati
1

Step-by-step explanation:

Total people killed in earthquake=5%

=5%=5/100

Total people survived = 8%

=8/10 = 43700

killed = 5/100 ×43700

= 2185

Total population = 43700+2185

= 45885

hope it is helpful.

mark as brain liest

Answered by swagir24
1

Answer:

Step-by-step explanation:

Let the initial population be x.

Killed = 5% of x

=5x/100

Remaining= x - 5x/100

=95x/100

People who left=8% of 95x/100

=38x/500

Current population= 95x/100 - 38x/500

=437x/500

But given current population is: 43700

So, 437x/500=43700

x= (43700*500 )/437

=50000

So, there were originally 50000 people in the town.

Hope it helped!

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