Question

5% of voters in an election did not cast their vote in the election there were only two candidates the winner by retaining 52% of the total body peated his competitor by 2280 votes the total number of voters was​

Answer 1

The total number of voters was 60,000.

Step-by-step explanation:

Let the total number of voters is x.

Given:

• 5% of voters in an election did not cast their vote in the election.

The total number of voters who voted is 95% i.e. 0.95x.

• The winner by retaining 52% of the total body beated his competitor by 2280 votes.

$\rightarrow 52\% \: of \: 0.95x \\\rightarrow \: \: 0.52 \times 0.95x \\ \rightarrow \:0.494x$

The winner candidate has 0.494x number of votes.

$\rightarrow \:0.95x - 0.494x \\ \rightarrow \:0.456x$

The loser candidate has 0.456x number of votes.

$\rightarrow \:0.494x - 0.456x = 2280 \\ \rightarrow \:0.038x = 2280 \\ \rightarrow \:x = \frac{2280}{0.038} \\ \rightarrow \:x = 60000$

So, the total number of voters was 60,000.