Math, asked by maheshkore342, 11 months ago

5% of voters in an election did not cast their votes in the election there were only two candidates the winner by obtaining 52% of the total votes defeated his his competitor by 2280 votes the total number of voters was​

Answers

Answered by kanikasharma1908
3

5% of voters in an election did not cast their votes in the election there were only two candidates the winner by obtaining 52% of the total votes defeated his his competitor by 2280 votes the total number of voters was​ 32,000 which can be explained as follows:

Step-by-step explanation:

5% of the people did not cast the vote. Hence 100-5=95% of the people casted their vote.

Winner obtained 52% , and since there were only two candidates, hence the loser obtained 95-52=43%

Winner received 52%, Loser=43%

Hence , the percentage margin by which winner won is (52-43)=9 %

Let total number of votes be y

Hence 9% of y =2880

So y=2880/9%=32000

                                        Hence, total no of voters is 32000

Similar questions