5 ohm,10 ohm,15 ohm are connected in series find its effective. Now first two resistance are in parallel then find its effective
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If in series, the answer will be 5+10+15 = 30 ohm.
If the first two in parallel, then 1/5 + 1/10 = 1/x where x will be 10/3 that is 3.33 ohm.
If the first two in parallel, then 1/5 + 1/10 = 1/x where x will be 10/3 that is 3.33 ohm.
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Answer:
If the circuit is in series then the effective resistance will be
5+10+15=30ohm
If the first 2 resistors are in parallel then
(1/5+1/10)+15
3/10
(10/3)+15
3.3+15
18.3ohm
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