5. One of the diagonals of a shombus in 12 on and its area
is 54 cm?, then find its perimeter. [Ans 1200 cm]
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Answered by
1
let other diagonal be x
area of rhombus = 1/2 ( 12x)
54 = 1/2. ( 12x)
108 = 12x
x= 9
side = √( 81/4 + 36) = √(81+ 144)/2
= √( 225)/2
= 15/2
perimeter = 4( 15/2) = 30
Answered by
3
Answer:
We know that:
Area of a rhombus = 1/2 × product of diagonals
Let one diagonal be = y
54 = 1/2 × 12 × y
=> y = 54 × 2/ 12
=> y = 9 cm
Side^2 = (9/2)^2 + (12/2)^2
Side^2 = 81/4 + 144/4
Side^2 = 225/4
Side = 15/2
Perimeter = 4 (15/2)
Perimeter = 15×2
Perimeter = 30 cm
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