Math, asked by animesh79, 1 year ago

5. One of the diagonals of a shombus in 12 on and its area
is 54 cm?, then find its perimeter. [Ans 1200 cm]​

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Answered by Anonymous
1

let other diagonal be x

area of rhombus = 1/2 ( 12x)

54 = 1/2. ( 12x)

108 = 12x

x= 9

side = √( 81/4 + 36) = √(81+ 144)/2

= √( 225)/2

= 15/2

perimeter = 4( 15/2) = 30

Answered by Anonymous
3

Answer:

We know that:

Area of a rhombus = 1/2 × product of diagonals

Let one diagonal be = y

54 = 1/2 × 12 × y

=> y = 54 × 2/ 12

=> y = 9 cm

Side^2 = (9/2)^2 + (12/2)^2

Side^2 = 81/4 + 144/4

Side^2 = 225/4

Side = 15/2

Perimeter = 4 (15/2)

Perimeter = 15×2

Perimeter = 30 cm

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